Question
Physics Question on projectile motion
A particle, when projected at 15° horizontally, has a range of 50 m. Find the range when projected at 45° with horizontal.
A
50 m
B
100 m
C
80 m
D
120 m
Answer
100 m
Explanation
Solution
When a particle is projected with initial velocity u at angle 𝜃 with the horizontal, then the horizontal range is given by
R=u2 sin 2g
For, 𝜃 = 15°, R = 50 m
Therefore, u2g=Rsin 2=50sin 30=100
Now, we have to find horizontal range, when the 𝜃 = 45°
Using,
R=u2 sin 2g=100sin (245)
R=100sin 90=100 m
Answer. B