Question
Question: A particle starts moving in xy – plane at 2 m/s along x – axis. 2 second later, its velocity is 4 m/...
A particle starts moving in xy – plane at 2 m/s along x – axis. 2 second later, its velocity is 4 m/s in a direction making 600 with positive x – axis. Its average acceleration for this period of motion is:
A
5 m/s2, along y – axis
B
3 m/s2, along y – axis
C
5 m/s2, at 600 with positive x – axis
D
3 m/s2, at 600 with positive x – axis
Answer
3 m/s2, along y – axis
Explanation
Solution

a=ΔtVf−Vi
= 2[4cos60i^+4sin60j^]−[2i^] = 2(2i^+23j^)−2i^ = 3j^
m/s2