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Question

Physics Question on Motion in a straight line

A particle starts from rest at t=0t=0 and moves in a straight line with an acceleration as shown in figure. The velocity of the particle at t=3 st=3\text{ }s is

A

2ms12\,m{{s}^{-1}}

B

4ms14\,m{{s}^{-1}}

C

6ms16\,m{{s}^{-1}}

D

8ms18\,m{{s}^{-1}}

Answer

4ms14\,m{{s}^{-1}}

Explanation

Solution

Velocity at 3s=3s= total algebraic sum of area under the curve or
v=4×24×1v=4\times 2-4\times 1 =84=4ms1=8-4=4m{{s}^{-1}}