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Question: A particle starts from rest and moves with uniform acceleration. If covers a displacement of \({y^2}...

A particle starts from rest and moves with uniform acceleration. If covers a displacement of y2x2{y^2} - {x^2} in the first 10s10s and y2+x2{y^2} + {x^2} in the next first 10s10s, then:
A) x=2x = \sqrt 2
B) x=3yx = 3y
C) y=3xy = 3x
D) y=2xy = \sqrt 2 x

Explanation

Solution

In the question, the displacement of the particle in the next first 10s10s implies that the time taken for the displacement is 20s20s. Now, applying the equations of motion, two relations between displacement and time can be obtained. Solving them we can obtain the required solution.

Complete step by step solution:
From the question, we know that the particle moves with uniform acceleration. This means it travels an equal distance in equal intervals of time.
Since, the acceleration of the body remains constant throughout the motion, we can say the acceleration of the body in the first 10s10s and in the next first 10s10s are the same.
Now, using the third equation of motion, we know:
S=ut+12at2S = ut + \dfrac{1}{2}a{t^2}
Where:
SS is the displacement of the body
uu is the initial velocity of the body
aa is the acceleration of the body
tt is the time taken by the body to cause the given displacement.
As in the question, it is given that the body starts from rest, we can write that the initial velocity is zero.
Therefore, u=0u = 0
Therefore, the equation of motion modifies to:
S=12at2\Rightarrow S = \dfrac{1}{2}a{t^2}
Now, it is given, that displacement is y2x2{y^2} - {x^2} in the first 10s10s , so we write:
y2x2=12a(10)2\Rightarrow {y^2} - {x^2} = \dfrac{1}{2}a{(10)^2}
y2x2=50a.......(1)\Rightarrow {y^2} - {x^2} = 50a.......(1)
And the displacement is y2+x2{y^2} + {x^2}in the next first10s10s, therefore, similarly we write:
y2+x2+y2x2=12a(20)2\Rightarrow {y^2} + {x^2} + {y^2} - {x^2} = \dfrac{1}{2}a{(20)^2}
2y2=200a\Rightarrow 2{y^2} = 200a
y2=100a......(2)\Rightarrow {y^2} = 100a......(2)
Now, solving equation (1)(1) and(2)(2), we obtain:
y2=2x2\Rightarrow {y^2} = 2{x^2}
Therefore, we can write:
y=2x\Rightarrow y = \sqrt 2 x
This is the required solution.

Hence, option (D) is correct.

Note: The equation of motions defines the behavioural motion of a particle or body with respect to time. Using these equations of motion, we can draw the graphs of the motion. This enables us to obtain various quantities like acceleration, velocity, their instantaneous values and various other unknown quantities.