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Question

Question: A particle starting from rest travels a distance \(x\) in first 2 seconds and a distance \(y\) in ne...

A particle starting from rest travels a distance xx in first 2 seconds and a distance yy in next two seconds, then

A

y=xy = x

B

y=2xy = 2x

C

y=3xy = 3x

D

y=4xy = 4x

Answer

y=3xy = 3x

Explanation

Solution

If particle starts from rest and moves with constant acceleration then in successive equal interval of time the ratio of distance covered by it will be

1:3:5:71:3:5:7 .....(2n1)(2n - 1)

i.e. ratio of x and y will be 1:31:3 i.e. xy=13\frac{x}{y} = \frac{1}{3}y=3xy = 3x