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Question: A particle projected with the speed u at an angle a with the horizontal acquires a velocity v when i...

A particle projected with the speed u at an angle a with the horizontal acquires a velocity v when it is at an angle b with the horizontal. Then –

A

v = ucos⁡β\frac{u}{\cos\beta}

B

v = u cosb

C

v = ucos⁡βcos⁡α\frac{u\cos\beta}{\cos\alpha}

D

v = ucos⁡αcos⁡β\frac{u\cos\alpha}{\cos\beta}

Answer

v = ucos⁡αcos⁡β\frac{u\cos\alpha}{\cos\beta}

Explanation

Solution

v cos b = u cos a

v = ucos⁡αcos⁡β\frac { \mathrm { u } \cos \alpha } { \cos \beta }