Question

A particle performing uniform circular motion has angular momentum $L$. If its angular frequency is doubled and its kinetic energy halved, then the new angular momentum is

• A. $L/4$
• B. $4L$
• C. $2L$
• D. $L/2$

Answer 1

Answer: (A)

$L/4$

Answer 2

Angular momentum of a particle performing uniform circular motion $L = I?$ Kinetic energy, $K=\frac{1}{2}\omega^{2}$ Therefore, $L=\frac{2K}{\omega^{2}}\omega=\frac{2K}{\omega}$ $\frac{L_{1}}{L_{2}}=\frac{K_{1}\omega_{2}}{K_{2}\omega_{1}}$ $\frac{L_{1}}{L_{2}}=2\times2=4 L_{1}=\frac{L}{4}$