Question

A particle performing simple harmonic motion is such that its amplitude is 4 m and speed of particle at mean position is 10 m/s. Find the distance of particle from mean position where velocity becomes 5 m/s.

• A. $\sqrt3\; m$
• B. $2\sqrt3\; m$
• C. $\frac{\sqrt3}{2}\; m$
• D. $\frac{1}{\sqrt2}\; m$

Answer 1

Answer: (B)

$2\sqrt3\; m$

Answer 2

The Correct Option is (B): $2\sqrt3$ $m$