Question

A particle perform simple harmonic motion. The equation of its motion is $x = 5\sin(4t - \frac{\pi}{6})$. Where x is its displacement. If the displacement of the particle is 3 units then its velocity is

• A. $2\pi/3$
• B. $5\pi/6$
• C. 20
• D. 16

Answer 1

Answer: (D)

16

Answer 2

$v = \omega\sqrt{a^{2} - y^{2}} = 4\sqrt{5^{2} - 3^{2}}$= 16

[As ω = 4, a = 5, y = 3]