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Question: A particle of mass m<sub>1</sub> is fastened to one end of a string and one of m<sub>2</sub> to the ...

A particle of mass m1 is fastened to one end of a string and one of m2 to the middle point, the other end of the string being fastened to a fixed point on a smooth horizontal table. The particle are then projected, so that the two portions of the string are always in the same straight line and describes horizontal circles. Find the ratio of tensions in the two parts of the string-

A

m1m1+m2\frac{m_{1}}{m_{1} + m_{2}}

B

m1+m2m1\frac{m_{1} + m_{2}}{m_{1}}

C

2m1+m22m1\frac{2m_{1} + m_{2}}{2m_{1}}

D

2m1m1+m2\frac{2m_{1}}{m_{1} + m_{2}}

Answer

2m1+m22m1\frac{2m_{1} + m_{2}}{2m_{1}}

Explanation

Solution

for m1 : - T1= m1w2(2r) …...(i)

for m2 : - T2 – T1 = m­2w2r ….(ii)