Question

A particle of mass m oscillates with simple harmonic motion between points x1 and x2, the equilibrium position being O. Its potential energy is plotted. It will be as given below in the graph:

• A.
• B.
• C.
• D.

Answer 1

Answer: (A)

Answer 2

PE in SHM =$\frac{1}{2}$Kx2[equation of parabola]
The potential energy of particles performing SHM varies parabolically in such a way that at the mean position, it becomes zero and maximum at extreme position.