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Question

Physics Question on torque

A particle of mass mm moves in the XYXY plane with a velocity ' vv ' along the straight line ABA B. If the angular momentum of the particle with respect to origin OO is LAL _{ A } when it is at AA and LBL_{B} when it is at BB, then

A

LA>LBL_{A}>L_{B}

B

LA=LBL_{A}=L_{B}

C

the relationship between LAL _{ A } and LBL _{ B } depends upon the slope of the line ABAB

D

LA<LBL_{A} < L_{B}

Answer

LA=LBL_{A}=L_{B}

Explanation

Solution

From the definition of angular momentum, L=r×p=rmvsinϕ(k^)\vec{ L }=\vec{ r } \times \vec{ p }=r m v \sin \phi(-\hat{ k })