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Physics Question on Centripetal forces

A particle of mass π‘š is under the influence of the gravitational field of a body of mass 𝑀 (≫ π‘š). The particle is moving in a circular orbit of radius π‘Ÿ0π‘Ÿ_0 with time period 𝑇0𝑇_0 around the mass 𝑀. Then, the particle is subjected to an additional central force, corresponding to the potential energy 𝑉c(π‘Ÿ) = π‘šπ›Ό/π‘Ÿ 3 , where 𝛼 is a positive constant of suitable dimensions and π‘Ÿ is the distance from the center of the orbit. If the particle moves in the same circular orbit of radiusπ‘Ÿ0 π‘Ÿ_0 in the combined gravitational potential due to 𝑀 and 𝑉c(π‘Ÿ), but with a new time period 𝑇1𝑇_1, then(𝑇12βˆ’π‘‡02)/𝑇12 (𝑇_1^2 βˆ’ 𝑇_0^ 2 )/𝑇_1^ 2 is given by [𝐺 is the gravitational constant.]

A

3Ξ±πΊπ‘€π‘Ÿ02\frac{3\alpha}{ πΊπ‘€π‘Ÿ_0^2}

B

Ξ±2πΊπ‘€π‘Ÿ02\frac{\alpha}{ 2πΊπ‘€π‘Ÿ_0^2}

C

Ξ±πΊπ‘€π‘Ÿ02\frac{\alpha}{ πΊπ‘€π‘Ÿ_0^2}

D

2Ξ±πΊπ‘€π‘Ÿ02\frac{2\alpha}{πΊπ‘€π‘Ÿ_0^2}

Answer

3Ξ±πΊπ‘€π‘Ÿ02\frac{3\alpha}{ πΊπ‘€π‘Ÿ_0^2}

Explanation

Solution

The correct option is (A):3Ξ±πΊπ‘€π‘Ÿ02\frac{3\alpha}{ πΊπ‘€π‘Ÿ_0^2}