Question

A particle of mass m is projected with a velocity $6 \hat { \dot { i } } + 8 \hat { \mathrm { j } }$ . Find the change in momentum when it just touches ground.

• A. 0
• B. 12 m
• C. 16 m
• D. 20 m

Answer 1

Answer: (C)

16 m

Answer 2

∆p = m(v_f – v_i) = m $[ ( 6 \hat { \mathbf { i } } - 8 \hat { \mathbf { j } } ) - ( 6 \hat { \mathbf { i } } + 8 \hat { \mathbf { j } } ) ] = - 16 \mathrm {~m} \hat { \mathrm { j } }$ .

|∆p|= 16