Question

A particle of mass 𝑚 is moving in the xy-plane such that its velocity at a point (x, y) is given as $\overrightarrow{v}=a(y\^{x}+2x\^{y})$ where 𝛼 is a non-zero constant. What is the force F acting on the particle?

• A. $\overrightarrow{𝐹} = 2ma^2(x\^{x}+y\^{y})$
• B. $\overrightarrow{𝐹} = ma^2(y\^{x}+2x\^{y})$
• C. $\overrightarrow{𝐹} = 2ma^2(y\^{x}+x\^{y})$
• D. $\overrightarrow{𝐹} = ma^2(x\^{x}+2y\^{y})$

Answer 1

Answer: (A)

$\overrightarrow{𝐹} = 2ma^2(x\^{x}+y\^{y})$

Answer 2

The correct option is(A): $\overrightarrow{𝐹} = 2ma^2(x\^{x}+y\^{y})$