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Question

Question: A particle of mass m is moving in a circular path of constant radius r such that is centripetal acce...

A particle of mass m is moving in a circular path of constant radius r such that is centripetal acceleration a is varying with time t as ac = k2rt, where k is a constant. The power delivered to the particle by force acting on it is

A

2πmk2r2

B

mk2r2t

C

mk4r2t53\frac{mk^{4}r^{2}t^{5}}{3}

D

Zero

Answer

mk2r2t

Explanation

Solution

ac = k2rt2

i.e., v2r=k2rt2\frac{v^{2}}{r} = k^{2}rt^{2} or v = krt

Also atdVdt=kr\frac{dV}{dt} = kr

∴ F = mat= mkr

Then, power = Fv = mkr(krt) = mk2r2t