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Question

Physics Question on work, energy and power

A particle of mass MM is moving in a circle of fixed radius RR in such a way that its centripetal acceleration at time tt is given by n2Rt2n^2 \, R \, t^2 where nn is a constant. The power delivered to the particle by the force acting on it, is :

A

Mn2R2tM \, n^2 R^2 t

B

MnR2tM \, n \, R^2 t

C

MnR2t2M \, n R^2 t^2

D

12Mn2R2t2\frac{1}{2} M \, n^2 R^2 t^2

Answer

Mn2R2tM \, n^2 R^2 t

Explanation

Solution

The correct option is(A): Mn2R2tM \, n^2 R^2 t

V2R=n2Rt2\frac{V^{2}}{R}=n^{2}\, R t^{2}
V2=n2R2t2\Rightarrow V^{2}=n^{2}\, R^{2}\, t^{2}
V=nRt\Rightarrow V=n R t
dVdt=nR\Rightarrow \frac{d V}{d t}=n R
P=FtVP=F_{t} V
=mdVdtV=\frac{m d V}{d t} V
=mnR.nRt=m n R .n R t
P=n2R2tmP=n^{2}\, R^{2}\, t\, m