Solveeit Logo

Question

Physics Question on Gravitation

A particle of mass mm is kept at rest at a height 3R3R from the surface of earth, where RR is radius of earth and MM is mass of earth. The minimum speed with which it should be projected, so that it does not return back, is : (g is acceleration due to gravity on the surface of earth)

A

(GM2R)12\left(\frac{GM}{2R}\right){^{\frac{1}{2}}}

B

(gR4)12\bigg( \frac {gR}{4}\bigg){^{\frac{1}{2}}}

C

(2gR)12\bigg( \frac {2g}{R}\bigg){^{\frac{1}{2}}}

D

(GMR)12\bigg( \frac {GM}{R}\bigg){^{\frac{1}{2}}}

Answer

(GM2R)12\left(\frac{GM}{2R}\right){^{\frac{1}{2}}}

Explanation

Solution

The minimum speed with which the particle should be projected from the surface of the earth so that it does not return back is known as escape speed and it is given by
Ve=2GM(R+h)V_e = \sqrt \frac {2GM}{(R+h)}
Here, h=3Rh = 3R
ve=2GM(R+3R)=2GM4R=GM2R\therefore v_e = \sqrt \frac {2GM}{(R + 3R)} = \sqrt \frac {2GM}{4R}=\sqrt \frac {GM}{2R}
=gR2(g=GMR2)= \sqrt \frac {gR}{2} \bigg(\because g = \frac {GM}{R^2} \bigg)