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Question

Physics Question on Oscillations

A particle of mass mm is executing oscillation about the origin on X-axis. Its potential energy is V(x)=Kx3V(x) = K|x|^3. Where KK is a positive constant. If the amplitude of oscillation is aa, then its time period TT is proportional to

A

1a\frac {1}{\sqrt a}

B

aa

C

a\sqrt a

D

a32a^{\frac 32}

Answer

1a\frac {1}{\sqrt a}

Explanation

Solution

The correct option is (A): 1a\frac {1}{\sqrt a}.