Question
Physics Question on Moving charges and magnetism
A particle of mass M and positive charge Q, moving with a constant velocity u1=4i^ms−1, enters a region of uniform static magnetic field normal to the x-y plane. The region of the magnetic field extends from x= 0 to x=L for all values of y. After passing through this region, the particle emerges on the other side after 10 milliseconds with a velocity u2=2(3i+j^)m/s−1. The correct statement(s) is (are)
the direction of the magnetic field is - z direction.
the direction of the magnetic field is +z direction
the magnitude of the magnetic field is 3Q50πMunits.
the magnitude of the magnetic field is 3Q100πM units.
the magnitude of the magnetic field is 3Q50πMunits.
Solution
So magnetic field is along −ve,z-direction.
Time taken in the magnetic field =10×10−3=6QBπM
B=60×10−3QπM=60Q1000πM
=3Q50πM