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Question

Physics Question on Moving charges and magnetism

A particle of mass MM and positive charge QQ, moving with a constant velocity u1=4i^ms1u _{1}=4 \hat{i}ms ^{-1}, enters a region of uniform static magnetic field normal to the xx-y plane. The region of the magnetic field extends from x=x = 0 to x=Lx = L for all values of yy. After passing through this region, the particle emerges on the other side after 10 milliseconds with a velocity u2=2(3i+j^)m/s1\vec{ u }_{2}=2(\sqrt{3} i +\hat{ j }) m / s ^{-1}. The correct statement(s) is (are)

A

the direction of the magnetic field is - z direction.

B

the direction of the magnetic field is +z direction

C

the magnitude of the magnetic field is 50πM3Q\frac{50\pi M}{3Q}units.

D

the magnitude of the magnetic field is 100πM3Q\frac{100 \pi M}{3Q} units.

Answer

the magnitude of the magnetic field is 50πM3Q\frac{50\pi M}{3Q}units.

Explanation

Solution

So magnetic field is along ve,z-ve, \,z-direction.
Time taken in the magnetic field =10×103=πM6QB=10 \times 10^{-3}=\frac{\pi M }{6 QB }
B=πM60×103Q=1000πM60QB =\frac{\pi M }{60 \times 10^{-3} Q }=\frac{1000 \pi M }{60 Q }
=50πM3Q=\frac{50 \pi M }{3 Q }