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Question

Physics Question on Mechanics and General Properties of Matter

A particle of mass m and angular momentum L moves in space where its potential energy is U(r) = kr2 (k > 0) and r is the radial coordinate.
If the particle moves in a circular orbit, then the radius of the orbit is

A

(L2mk)14(\frac{L^2}{mk})^{\frac{1}{4}}

B

(L22mk)14(\frac{L^2}{2mk})^{\frac{1}{4}}

C

(2L2mk)14(\frac{2L^2}{mk})^{\frac{1}{4}}

D

(4L2mk)14(\frac{4L^2}{mk})^{\frac{1}{4}}

Answer

(L22mk)14(\frac{L^2}{2mk})^{\frac{1}{4}}

Explanation

Solution

The correct answer is (B) : (L22mk)14(\frac{L^2}{2mk})^{\frac{1}{4}}