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Question: A particle of mass m = 9 × 10<sup>–31</sup> kg moving towards the wall of a vessel at a velocity of ...

A particle of mass m = 9 × 10–31 kg moving towards the wall of a vessel at a velocity of v = 600 ms–1 strikes it at an angle of 60° to the normal and rebounds at the same angle at the same speed. The impulse of the force experienced by the wall during the impact is –

A

3 × 1021 N s

B

9 × 10–28 N s

C

5.4 × 10–28 N s

D

5.4 × 10–27 N s

Answer

5.4 × 10–28 N s

Explanation

Solution

Impulse = change in momentum = 2 mv cosq