Question

A particle of mass 200 gm executes S.H.M. The restoring force is provided by a spring of force constant 80 N/m. The time period of oscillations is

• A. 0.31 sec
• B. 0.15 sec
• C. 0.05 sec
• D. 0.02 sec

Answer 1

Answer: (A)

0.31 sec

Answer 2

$T = 2\pi\sqrt{\frac{m}{k}} = 2\pi\sqrt{\frac{0.2}{80}} = \frac{2\pi}{20} = 0.31\sec$.