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Question

Physics Question on work, energy and power

A particle of mass 100g100\,g is thrown vertically upwards with a speed of 5m/s5m/s . the work done by the force of gravity during the time the particle goes up is

A

1.25J-1.25\,J

B

1.25J1.25\,J

C

0.5J0.5\,J

D

0.5J-0.5\,J

Answer

1.25J-1.25\,J

Explanation

Solution

Maximum height reached by the particle


Hmax=u22g=(5)22×10=1.25mH_{\max }=\frac{u^{2}}{2 g}=\frac{(5)^{2}}{2 \times 10}=1.25\, m
Work done =Fd=Fdcosθ=\vec{ F } \cdot \vec{ d }=F d \cos \theta
=mg×(Hmax)×cos180=m g \times\left(H_{\max }\right) \times \cos 180^{\circ}
=0.1×10×1.25×(1)=1.25J=0.1 \times 10 \times 1.25 \times(-1)=-1.25\, J