Question

A particle of mass 10 grams is executing simple harmonic motion with an amplitude of 0.5 m and periodic time of $(\pi/5)$ seconds. The maximum value of the force acting on the particle is

• A. 25 N
• B. 5 N
• C. 2.5 N
• D. 0.5 N

Answer 1

Answer: (D)

0.5 N

Answer 2

Maximum force $= m(a\omega^{2}) = ma\left( \frac{4\pi^{2}}{T^{2}} \right)$

$= 0.5\left( \frac{4\pi^{2}}{\pi^{2}/25} \right) \times 0.01 = 0.5N$