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Question

Question: A particle of mass 10 grams is executing S.H.M. with an amplitude of 0.5 meter and circular frequenc...

A particle of mass 10 grams is executing S.H.M. with an amplitude of 0.5 meter and circular frequency of 10 radian/sec. The maximum value of the force acting on the particle during the course of oscillation is

A

25 N

B

5 N

C

2.5 N

D

0.5 N

Answer

0.5 N

Explanation

Solution

Maximum force = mass × maximum acceleration =mω2a=10×103(10)2(0.5)\mathbf{m}\mathbf{\omega}^{\mathbf{2}}\mathbf{a}\mathbf{= 10}\mathbf{\times}\mathbf{1}\mathbf{0}^{\mathbf{-}\mathbf{3}}\mathbf{(10}\mathbf{)}^{\mathbf{2}}\mathbf{(0.5)} = 0.5 N