Question

A particle of mass 10 gm is describing S.H.M. along a straight line with period of 2 sec and amplitude of 10 cm. Its kinetic energy when it is at 5 cm. From its equilibrium position is

• A. $37.5\pi^{2}erg$
• B. $3.75\pi^{2}erg$
• C. $375\pi^{2}erg$
• D. $0.375\pi^{2}erg$

Answer 1

Answer: (C)

$375\pi^{2}erg$

Answer 2

Kinetic energy $= \frac{1}{2}m\omega^{2}(a^{2} - y^{2}) = \frac{1}{2}10\frac{4\pi^{2}}{4}(10^{2} - 5^{2}) = 375\pi^{2}ergs$.