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Physics Question on Dual nature of matter

A particle of mass 1 mg has the same wavelength as an electron moving with a velocity of 3×106 ms−1.3 \times 10^6 \, ms^{-1}. The velocity of the particle is (mass of electron=9.1×10−31 kg)9.1 \times 10^{-31} \, kg)

A

3×10−31 ms−13 \times 10^{-31} \, ms^{-1}

B

2.7×10−21 ms−12.7 \times 10^{-21} \, ms^{-1}

C

2.7×10−18 ms−12.7 \times 10^{-18} \, ms^{-1}

D

9×10−2 ms−19 \times 10^{-2} \, ms^{-1}

Answer

2.7×10−18 ms−12.7 \times 10^{-18} \, ms^{-1}

Explanation

Solution

?=h10−6kg×v=h9.1×10−31kg×3×106 m/s?=\frac {h}{10^{-6}kg \times v}= \frac {h}{9.1 \times 10^{-31}kg \times 3 \times 10^6 \, m/s }
∴v=2.7×10−18m/s.\therefore v=2.7 \times 10^{-18} m/s.