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Question

Physics Question on laws of motion

A particle of mass 0.3kg0.3\, kg is subjected to a force F=kxF = - kx with k=15N/mk = 15\, N/m. What will be its initial acceleration, if it is released from a point 20cm20\, cm away from the origin ?

A

3m/s23\, m/s^2

B

15m/s215\, m/s^2

C

5m/s25\, m/s^2

D

10m/s210\, m/s^2

Answer

10m/s210\, m/s^2

Explanation

Solution

Given : m=0.3kg,x=20cmm = 0.3\, kg, x = 20\, cm, and k=15N/mk= 15\,N/ m F=kx...(i)F=-kx\,...(i) and F=ma...(ii)F=ma\,...(ii) ma=kxora=150.3×20×102\therefore ma=-kx or a=-\frac{15}{0.3}\times20\times10^{-2} a=153×2=10m/s2a=-\frac{15}{3}\times2=-10\,m/s^{2} \therefore Initial acceleration a=10m/s2a=10\,m/s^{2}