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Question: A particle of charge q , mass m and kinetic energy E enters in magnetic field perpendicular to it...

A particle of charge q , mass m and kinetic energy E enters in magnetic field perpendicular to its velocity and undergoes a circular arc of radius( r). Which of the following curves represents the variation of r with E ?

A

A straight line

B

A circle

C

A parabola

D

An ellipse

Answer

A parabola

Explanation

Solution

Here's the breakdown of why the answer is a parabola:

  1. Magnetic Force and Circular Motion: When a charged particle (charge q, mass m, velocity v) enters a magnetic field B perpendicularly, it experiences a magnetic force (F = qvB) that acts as the centripetal force, causing circular motion.

  2. Equating Forces:

    • Magnetic force: FB=qvBF_B = qvB
    • Centripetal force: Fc=mv2rF_c = \frac{mv^2}{r}
    • Equating: qvB=mv2rqvB = \frac{mv^2}{r}
  3. Radius (r) Formula: Solving for the radius r: r=mvqBr = \frac{mv}{qB}

  4. Kinetic Energy (E) Relation:

    • Kinetic energy: E=12mv2E = \frac{1}{2}mv^2
    • Solving for v: v=2Emv = \sqrt{\frac{2E}{m}}
  5. Substitute v into r Formula: r=mqB2Em=2mEqBr = \frac{m}{qB} \sqrt{\frac{2E}{m}} = \frac{\sqrt{2mE}}{qB}

  6. Relationship between r and E: The equation r=2mEqBr = \frac{\sqrt{2mE}}{qB} shows that r is proportional to the square root of E: rEr \propto \sqrt{E}

    This implies that if you plot r on the y-axis and E on the x-axis, the graph will be a parabola (specifically, the upper half of a parabola opening along the positive x-axis).