Question
Question: A particle of charge q , mass m and kinetic energy E enters in magnetic field perpendicular to it...
A particle of charge q , mass m and kinetic energy E enters in magnetic field perpendicular to its velocity and undergoes a circular arc of radius( r). Which of the following curves represents the variation of r with E ?
A straight line
A circle
A parabola
An ellipse
A parabola
Solution
Here's the breakdown of why the answer is a parabola:
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Magnetic Force and Circular Motion: When a charged particle (charge q, mass m, velocity v) enters a magnetic field B perpendicularly, it experiences a magnetic force (F = qvB) that acts as the centripetal force, causing circular motion.
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Equating Forces:
- Magnetic force: FB=qvB
- Centripetal force: Fc=rmv2
- Equating: qvB=rmv2
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Radius (r) Formula: Solving for the radius r: r=qBmv
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Kinetic Energy (E) Relation:
- Kinetic energy: E=21mv2
- Solving for v: v=m2E
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Substitute v into r Formula: r=qBmm2E=qB2mE
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Relationship between r and E: The equation r=qB2mE shows that r is proportional to the square root of E: r∝E
This implies that if you plot r on the y-axis and E on the x-axis, the graph will be a parabola (specifically, the upper half of a parabola opening along the positive x-axis).