Question

A particle of charge q and mass m is released in an electric field of intensity E, then the kinetic energy of the particle after time t will be - (all quantities in SI units)

• A. $\frac{1}{2}m(q^{2}E^{2}t^{2})$
• B. q²E²t²/2m
• C. qEt/2m
• D. (qE/2mt)²

Answer 1

Answer: (B)

q²E²t²/2m

Answer 2

F = qE Þ a =; v = u + at = (0) + $\left( \frac { q E } { m } \right) \mathrm { t }$

\ K.E. = $\frac { 1 } { 2 }$ mv² =