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Question: A particle of charge \(- 16 \times 10 ^ { - 18 }\) coulomb moving with velocity 10 m/s along the x...

A particle of charge −16×10−18- 16 \times 10 ^ { - 18 } coulomb moving with velocity 10 m/s along the x-axis enters a region where a magnetic field of induction B is along the y-axis, and an electric field of magnitude 104 V/m is along the negative z-axis. If the charged particle continuous moving along the x-axis, the magnitude of B is

A

10−3 Wb/m210 ^ { - 3 } \mathrm {~Wb} / \mathrm { m } ^ { 2 }

B

103 Wb/m210 ^ { 3 } \mathrm {~Wb} / \mathrm { m } ^ { 2 }

C

105 Wb/m210 ^ { 5 } \mathrm {~Wb} / \mathrm { m } ^ { 2 }

D

1016 Wb/m210 ^ { 16 } \mathrm {~Wb} / \mathrm { m } ^ { 2 }

Answer

103 Wb/m210 ^ { 3 } \mathrm {~Wb} / \mathrm { m } ^ { 2 }

Explanation

Solution

Particles is moving undeflected in the presence of both electric field as well as magnetic field so it's speed

⇒B=Ev\Rightarrow B = \frac { E } { v } =10410=103 Wb/m2= \frac { 10 ^ { 4 } } { 10 } = 10 ^ { 3 } \mathrm {~Wb} / \mathrm { m } ^ { 2 }