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Question

Question: A particle moving with a velocity 1/10<sup>th</sup> of that of light will cross a nucleus in about-...

A particle moving with a velocity 1/10th of that of light will cross a nucleus in about-

A

10–47 s

B

10–22 s

C

10–12 s

D

10–8 s

Answer

10–22 s

Explanation

Solution

t = 2rv=21015m3×107m/s=23×1022s\frac{2r}{v} = \frac{210^{–15}m}{3 \times 10^{7}m/s} = \frac{2}{3} \times 10^{–22}s