Question
Question: A particle moving in one dimension with a constant acceleration of \[a = 2m/{s^2}\] is observed to c...
A particle moving in one dimension with a constant acceleration of a=2m/s2 is observed to cover a distance of 5m during a particular interval of1s. The distance covered by the particle in the next 1s interval is in metre:
A)5
B)6
C)7
D)10
Solution
Acceleration is a vector quantity which tells about magnitude and direction. It is the rate of change of velocity with respect to time. Constant acceleration means that the moving object or particle is changing its velocity by a constant interval of time. The objects falling freely under the effect of gravity often have a constant acceleration. Acceleration is the result of unbalanced force and the net force gives the direction of acceleration.
Step-by-Step Explanation:
Step I: Given acceleration, a=2m/s2
In 1 sec, the distance covered is, S=5m
Let ‘u’ be the initial velocity.
Step II: Using distance formula,S=ut+21at2
Put values of S, a and t, and find the value of u.
5=(u×1)+21×2×(1)2
5=u+1
u=5−1
u=4m/s
Initial Velocity of the object is, u=4m/s.
Step III: If Distance covered in next one second is to be calculated, then value of t=1+1
Value of t=2sec
Again using distance formula,S=ut+21at2
Substituting values of u, a and t; find value of S.
S=(4×2)+21×2×(2)2
S=8+4
S=12m
Step IV: Distance covered in 1stsecond, S1=5m
Distance covered in two seconds, S2=12m
Distance covered in next one second, S=S2−S1
S=12−5
S=7m
Distance covered in the interval of the next one second is =7m.
Hence, option C is the right answer.
Note: One dimensional motion of an object means that the object is moving only in one direction. In one dimension the object moves in a straight line. The motion of an object is generally represented in a direction of positive x-axis. Some daily life examples of one dimensional motion includes; an athlete running on a straight racing track, or a person walking straight on zebra crossing etc.