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Question

Physics Question on Uniform Circular Motion

A particle moving in a circular path has an angular momentum of L. If the frequency of rotation is halved, then its angular momentum becomes

A

L2\frac{L}{2}

B

L

C

L3\frac{L}{3}

D

L4\frac{L}{4}

Answer

L2\frac{L}{2}

Explanation

Solution

Answer (a) L2\frac{L}{2}