Question
Physics Question on work, energy and power
A particle moves with ,a velocity (5i^−3j^+6k^) m/s under the influence of a constant force F=10i^+10j^+12k^N. The instantaneous power applied to the particle is:
A
200 J/s
B
40 J/s
C
140 J/s
D
170 J/s
Answer
140 J/s
Explanation
Solution
V=(5i^−3j^+6k^)m/s F=(10i^+10j^+20k^)N ∴ Power P=F.v =(10i^+10j^+20k^).(5i^−3j^+6k^) =50−30+120 =140W