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Question

Physics Question on work, energy and power

A particle moves with ,a velocity (5i^3j^+6k^)(5\hat{i}-3\hat{j}+6\hat{k}) m/s under the influence of a constant force F=10i^+10j^+12k^N.\vec{F}=10\hat{i}+10\hat{j}+12\hat{k}N. The instantaneous power applied to the particle is:

A

200 J/s

B

40 J/s

C

140 J/s

D

170 J/s

Answer

140 J/s

Explanation

Solution

V=(5i^3j^+6k^)m/s\overrightarrow{V}=(5\hat{i}-3\hat{j}+6\hat{k})m/s F=(10i^+10j^+20k^)N\overrightarrow{F}=(10\hat{i}+10\hat{j}+20\hat{k})N \therefore Power P=F.v\overrightarrow{P}=\overrightarrow{F}.\overrightarrow{v} =(10i^+10j^+20k^).(5i^3j^+6k^)=(10\hat{i}+10\hat{j}+20\hat{k}).(5\hat{i}-3\hat{j}+6\hat{k}) =5030+120=50-30+120 =140W=140\,W