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Question

Question: A particle moves with a constant speed v along a circular path of radius r and completes the circle ...

A particle moves with a constant speed v along a circular path of radius r and completes the circle in time T. What is the acceleration of the particle

A

mgmg

B

2πvT\frac{2\pi v}{T}

C

πr2T\frac{\pi r^{2}}{T}

D

πv2T\frac{\pi v^{2}}{T}

Answer

2πvT\frac{2\pi v}{T}

Explanation

Solution

ac=v2r=ω2r=vωa_{c} = \frac{v^{2}}{r} = \omega^{2}r = v\omega =v(2πT)=2πvTv\left( \frac{2\pi}{T} \right) = \frac{2\pi v}{T}