Question

A particle moves such that its acceleration is given by

a = – b(x – 2) Here : b is a positive constant and x is the position from origin. Time period of oscillations is –

• A. $2 \pi \sqrt { \beta }$
• B. 2p $\sqrt { \frac { 1 } { \beta } }$
• C. 2p$\sqrt { \beta + 2 }$
• D. 2p $\sqrt { \frac { 1 } { \beta + 2 } }$

Answer 1

Answer: (B)

2p $\sqrt { \frac { 1 } { \beta } }$

Answer 2

a = – b(x – 2)

as a = – w²(x – x₀)

\ w² = b Ž T = 2p $\sqrt { \frac { 1 } { \beta } }$