Question

A particle moves such that its acceleration a is given by$a = - bx$, where x is the displacement from equilibrium position and b is a constant. The period of oscillation is

• A. $2\pi\sqrt{b}$
• B. $\frac{2\pi}{\sqrt{b}}$
• C. $\frac{2\pi}{b}$
• D. $2\sqrt{\frac{\pi}{b}}$

Answer 1

Answer: (B)

$\frac{2\pi}{\sqrt{b}}$

Answer 2

In the given case, $\frac{Displacement}{Acceleration} = \frac{1}{b}$

∴ Time period $T = 2\pi\sqrt{\frac{Displacement}{Acceleration}} = \frac{2\pi}{\sqrt{b}}$