Question

A particle moves in x – y plane along path ABCD as shown. When it is at point C angle between its instantaneous velocity and average velocity is:

• A. 80⁰
• B. 82⁰
• C. 98⁰
• D. 90⁰

Answer 1

Answer: (B)

82⁰

Answer 2

Average velocity is ∆$\overrightarrow{x}$/∆t, direction being along displacement vector ∆$\overrightarrow{x}$ that is along AC. Instantaneous velocity $\overrightarrow{V}$_ins is along the tangent on the path at C, that is along CD. Using geometrical construction, it is equal to (45⁰ + 37^0o) = 82⁰.