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Question

Physics Question on Motion in a plane

A particle moves in xyx-y plane according to rule x=asinωtx = a\,\sin\omega t and y=acosωty = a \,\cos\omega t. The particle follows

A

an elliptical path

B

a circular path

C

a parabolic path

D

a straight line path inclined equally to x and y-axes

Answer

a circular path

Explanation

Solution

x=asinωtx = a \sin \omega t or xa=sinωt\frac{ x}{a} =\sin \, \omega t ..(i)
y=acosωty = a \cos \omega t or ya=cosωt\frac{y}{a} = \cos \omega t ..(ii)
Squaring and adding, we get
x2a2+y2a2=1\frac{x^2}{a^2} + \frac{ y^2}{a^2} = 1 (cos2ωt+sin2ωt=1) ( \because \cos^2 \, \omega t + \sin^2 \, \omega t = 1)
or x2+y2=a2x^2 + y^2 = a^2
This is the equation of a circle. Hence particle follows a circular path.