Question
Question: A particle moves in a straight line with a constant acceleration. It changes its velocity from \[10m...
A particle moves in a straight line with a constant acceleration. It changes its velocity from 10ms−1 to 20ms−1 while passing through a distance 135m in t second. The value of t is
A. 12
B. 9
C. 10
D. 1.8
Explanation
Solution
Hint: Recall the equations of motion and apply the suitable equations consecutively for finding height attained by the stone and time taken. Equations of motion are as follows:
v=u+at
s=ut+21at2
v2=u2+2as
Complete step by step answer:
Given that,
Initial velocity, u=10ms−1
Final velocity, v=20ms−1
Distance covered, d=135m
Firstly, we will calculate acceleration(a), by applying 3rd equation of motion and after finding acceleration, we will calculate time (t) by applying 1st equation of motion.
Now, on applying 3rd equation of motion,