Question

A particle moves in a potential region given by

$U = 8 x ^ { 2 } - 4 x + 400$ J. Its state of equilibrium will be

• A. $x = 25 m$
• B.
• C.
• D.

Answer 1

Answer: (B)

Answer 2

$F = - \frac { d U } { d x } = - \frac { d } { d x } \left( 8 x ^ { 2 } - 4 x + 400 \right)$

For the equilibrium condition $F = - \frac { d U } { d x } = 0$

⇒ $16 x - 4 = 0$ ⇒$x = 4 / 16$∴ .