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Question

Physics Question on Motion in a plane

A particle moves in a circle of radius 20 cm. Its linear speed is given by v = 2t . where t is in s and v in m/s. Then

A

the radial acceleration at t=2sis80ms2 t = 2s is 80ms^{-2}

B

tangential acceleration at t=2sis2ms1t = 2s is 2 ms^{-1}

C

net acceleration at t = 2 s is greater than 80 ms1ms^{-1}

D

tangential acceleration remains constant in magnitude

Answer

tangential acceleration remains constant in magnitude

Explanation

Solution

v = 2t, ac=ν2r=(2t)20.2a_c = \frac{\nu^2}{r} = \frac{(2t)^2}{0.2} = 20t2^2 = 20 ×22\times 2^2 = 80 m/s2^2 at=dvdta_t = \frac{dv}{dt} = 2 m/s2^2 Net acceleration : a = ac2+at2\sqrt{a^2_c + a_t^2} > 80 m/s2^2