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Question: A particle moves in a circle of diameter 1 cm with a constant angular velocity. A concave mirror of ...

A particle moves in a circle of diameter 1 cm with a constant angular velocity. A concave mirror of focal length 10 cm is placed with its principal axis passing through the centre of the circle and perpendicular to its plane. The distance between the pole of the mirror and the centre of the circle is 30 cm. The ratio of acceleration of image to that of object is –

A

12\frac { 1 } { 2 }

B

14\frac { 1 } { 4 }

C

2

D

4

Answer

12\frac { 1 } { 2 }

Explanation

Solution

∣m∣=∣ff−u∣| \mathrm { m } | = \left| \frac { \mathrm { f } } { \mathrm { f } - \mathrm { u } } \right| = ∣−10−10+30∣\left| \frac { - 10 } { - 10 + 30 } \right| = 12\frac { 1 } { 2 }

12\frac { 1 } { 2 }

wo = wI

\ aIao\frac { \mathrm { a } _ { \mathrm { I } } } { \mathrm { a } _ { \mathrm { o } } } = rIro\frac { r _ { I } } { r _ { o } } =12\frac { 1 } { 2 }