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Question

Question: A particle moves from position \(3 \hat { i } + 2 \hat { j } - 6 \hat { k }\) to \(14 \hat { i } + 1...

A particle moves from position 3i^+2j^6k^3 \hat { i } + 2 \hat { j } - 6 \hat { k } to 14i^+13j^+9k^14 \hat { i } + 13 \hat { j } + 9 \hat { k } due to a uniform force of 4i^+j^+3k^N4 \hat { i } + \hat { j } + 3 \hat { k } N If the displacement in meters then work done will be

A

100 J

B

200 J

C

300 J

D

250 J

Answer

100 J

Explanation

Solution

S=r2r1S = \overrightarrow { r _ { 2 } } - \overrightarrow { r _ { 1 } }

W=FSW = \vec { F } \cdot \vec { S } =(4i^+j^+3k^)(11i^+11j^+15k^)= ( 4 \hat { i } + \hat { j } + 3 \hat { k } ) \cdot ( 11 \hat { i } + 11 \hat { j } + 15 \hat { k } )