Question
Question: A particle moves from A to P and from P to B, as shown in the figure. Find the path length and displ...
A particle moves from A to P and from P to B, as shown in the figure. Find the path length and displacement.
Solution
Hint: We need to determine the length AP and PB to answer this question. From the figure, it is clear that AP=PB. Also, we should know the distinction between path length and displacement.
Complete step by step answer:
From the figure, we can see that the ∠BPD=∠APC=60∘ (VOA) because they are vertically opposite angles. We also know that the sum of all the angles will be 360∘. So the other two angles which are equal (vertically opposite angles), can be found out by,
∠BPD+∠APC+∠APB+∠CPD=360∘60∘+60∘+2∠APB=360∘
∴∠APB=120∘
After figuring out ∠APB=120∘, we will drop a perpendicular from P to E on AB, which will divide AB into two equal parts AE and EB, which are equal sections of length 2e. The line PE splits the angle ∠APB into two equal angles, i.e. ∠APE=∠BPE=60∘.
Considering the right triangle AEP, we can write
sin(60∘)=APAE=AP(2e)
AP=sin(60∘)(2e)
∴AP=3e
So, due to symmetry, PB will also be equal to 3e.
So the path length is equal to the total distance travelled. So we can define path length as the sum of the lengths AP and PB,
P.L=AP+PB
P.L=32e.
So the path length is the distance that the particle travelled from A to P and from P to B, which is equal to (P.L)=32e.
But, the displacement will always be the shortest distance travelled; in this case, it will be the length of AB = e.
Note: In mechanics, displacement is a vector whose length is the shortest distance from the initial to the final position of a point P undergoing motion.
In mechanics, the Path length is the total distance travelled by the body from an initial point to a final point.