Question
Physics Question on Motion in a straight line
A particle moves along Y-axis in such a way that its y-coordinate varies with time t according to the relation y=3+5t+7t2. The initial velocity and acceleration of the particle are respectively
A
14m s−1,−5ms−2
B
19m s−1,−9m s−2
C
−14m s−1,−5m s−2
D
5m s−1,14m s−2
Answer
5m s−1,14m s−2
Explanation
Solution
Given y=3+5t+7t2
Velocity (v) is defined as rate of change of displacement, also
using dxdxn=nxn−1, we have
hence v=dtdy=5+15t
Initial velocity at t = 0, is
v=5ms−1
Also acceleration a =dt2d2y
=14ms−2