Question
Physics Question on Acceleration
A particle moves along Y-axis in such a way that its y− coordinate varies with time t according to the relation y=3+5t+7t2. The initial velocity and acceleration of the particle are respectively:
A
14ms−1,−5ms−2
B
19ms−1,−9ms−2
C
−14ms−1,−5ms−2
D
5ms−1,14ms−2
Answer
5ms−1,14ms−2
Explanation
Solution
Rate of change of position is known as velocity and rate of change of velocity is known as acceleration.
Given y=3+5t+7t2
Velocity (v) is defined as rate of change of displacement, also using
dxdxn=nxn−1,
we have ∴ v=dtdy=5+14t
Initial velocity at t=0, is v=5m/s.
Also acceleration a=dt2d2y=14m/s2