Question

A particle moves along X-axis in such a way that its coordinate X varies with time $t$ according to the equation$x = (2 - 5t + 6t^{2})m$. The initial velocity of the particle is

• A. $- 5m/s$
• B. $6m/s$
• C. $- 3m/s$
• D. $3m/s$

Answer 1

Answer: (A)

$- 5m/s$

Answer 2

The velocity of the particle is

$\frac{dx}{dt} = \frac{d}{dt}(2 - 5t + 6t^{2}) = (0 - 5 + 12t)$

For initial velocity $t = 0$, hence $v = - 5\mspace{6mu} m/s$.